Questions tagged [sobolev-spaces]

For questions about or related to Sobolev spaces, which are function spaces equipped with a norm that controls both a function and its weak derivatives in some Lebesgue space.

Sobolev spaces are function spaces generalizing the Lebesgue spaces. Whereas elements of Lebesgue spaces have certain integrability condition imposed on them, derivatives of functions in a Sobolev space are also required to be sufficiently integrable: that is, we require all (weak) partial derivatives of the function up to a certain order belong to a certain fixed Lebesgue space.

In more detail, let $U \subseteq \mathbb{R}^n$ be an open set. A weak $\alpha$th partial derivative $D^\alpha f$ of $f$ is a function $g\in L^1_{\mathrm{loc}}(U)$ such that $$\int_U f D^\alpha \phi \, dx = (-1)^{|\alpha|} \int g\phi \, dx$$ for each compactly supported smooth function $\phi \in C^\infty_c(U)$. the Sobolev space $W^{k, p}(U)$ consists of those functions $f\in L^p(U)$ such that for every multi-index $\alpha$ of length at most $k$, every weak partial derivative $D^{\alpha}f$ exists and is an element of $L^p$. The Sobolev spaces are equipped with norms defined by

$$\|u\|_{W^{k,p}(U)} = \begin{cases} \left( \sum_{|\alpha| \le k} \|D^{\alpha} u\|_{L^p(U)}^p \right)^{1/p} & p < \infty, \\ \max_{|\alpha| \le k} \|D^{\alpha}\|_{L^{\infty}(U)} &p=\infty .\end{cases}$$

$(W^{k,p}(U),\|\cdot\|_{W^{k,p}(U)})$ are Banach spaces for each $k\in\mathbb N$, and each $p\in[1,\infty]$. The norms measure both the size and the regularity of a function.

The basic fundamental result of Sobolev spaces is the Sobolev embedding theorem. In words, it says that (1) if $kp<n$, having $k$ weak derivatives in $L^p$ places your function in a better Lebesgue space $L^{p^*}$, where $\frac1{p^*} = \frac1p - \frac kn$, and (2) if $kp>n$, then your function is not only in $L^\infty$ but also has a continuous representative in some space of Hölder continuous functions. In particular, sufficiently many weak derivatives means that your function is in fact classically differentiable.

Reference: Sobolev space.

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Suppose that there exist a set $\Gamma$ of positive measure such that $\nabla u=0, a.e.\ x\in\Gamma$.

Suppose $\Omega\subset\mathbb{R}^n$ is a bounded domain. Let $u\in H_0^1(\Omega)$ and $\tilde{u}\in L^2(\Omega)$ satisfies $$\int_\Omega\nabla u\nabla v=\int_\Omega \tilde{u}v,\ \forall\ v\in C_0^{\infty}(\Omega)$$ Suppose that there exist a set…
Tomás
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The dual of the Sobolev space $W^{k,p}$

The dual of the Sobolev space if defined to be $$(W^{k,p}(\Omega))' = W_0^{-k,p'}(\Omega)$$ where $\frac 1 p + \frac 1 {p'} = 1$. Why makes this definition sense, especially why do we have $L^{p'}$-functions on right side that vanish on $\partial…
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Intuition behind losing half a derivative via the trace operator

This is an informal question, but here goes: For a function $f \in H^s(\Omega)$ ($s > 1/2$), there is a well-defined operator (the trace) $T$ such that $Tf = f\vert_{\partial \Omega}$ if $f \in C^\infty \cap H^s(\Omega)$ (so that it agrees with…
BaronVT
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$C^\infty$ dense in Sobolev spaces

I'm reading a theorem which says that $C^\infty$ intersection with $W^{k,p}$ is dense in $W^{k,p}$. I don't understand why they take the intersection. Isn't it $C^\infty$ a subspace of $W^{k,p}$? Thanks.
inquisitor
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Sobolev Embedding (Case: p=N)

Let $\Omega\subset\mathbb{R}^N$ be a regular bounded domain. Suppose $p=N$, then by Sobolev theorem, we have that for fixed $q\in [1,\infty)$ $$\|u\|_q\leq C\|u\|_{1,N}\ ,\forall\ u\in W^{1,N}(\Omega)$$ for some constant $C$. Moreover, the…
Tomás
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Extension Theorem for the Sobolev Space $W^{1, \infty}(U)$

I am trying to find a way of extending functions in the Sobolev Space $W^{1, \infty}(U)$ to $W^{1, \infty}(\mathbb{R}^n)$ where $U\subset\mathbb{R}^{n}$ is open such that $U\subset\subset V$ for $V\subset\mathbb{R}^{n}$ also open and bounded.…
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Confusion about the closure of $\mathcal{D}(\Omega)$ in $H^s(\mathbb{R}^n)$

On page 77 of his book Strongly Elliptic Systems and Boundary Integral Equations, McLean defines the Sobolev space $\tilde{H}^s(\Omega)$ as $$\tilde{H}^s(\Omega)=\text{closure of}\ \mathcal{D}(\Omega)\ \text{in}\…
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Example of a discontinuous and bounded function for the limiting case $W^{1,n}$

Let $\Omega = B(0,1)$ be the open unit disc in $\mathbb{R}^2$. I'm looking for an example of a discontinuous and bounded function in $W^{1,2}(\Omega)$. I know the example $u(x) = \log \left( \log \left(1 + \frac{1}{|x|}\right)\right)$ of a…
levap
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Sobolov Space $W^{2,2}\cap W^{1,2}_0$ norm equivalence

I would like to know why on $W^{2,2}\cap W^{1,2}_0$ the norms $$ ||u|| _{W^{2,2}}=\sum_{|\alpha|\leq 2}||D^\alpha u||_{L^2}$$ and $$||\Delta u||_{L^2}$$ are equivalent.
testrado
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Equivalent Norms on Sobolev Spaces

Let $u$ be in the Sobolev space $H^2$. Then the standard definition of the norm is $$ ||u||_{H^2}^2 = \sum_{|\alpha| \leq 2} ||D^{\alpha} u||_{L^2}^2. $$ However, I have also seen it defined this way $$ ||u||_{H^2}^2 = ||u||_{L^2}^2 +…
al0
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Why is $H^1 \neq H_0^1$?

I've been doing some reading on Sobolev-spaces and one remark said that $H_0^1$, i.e. the space of $H^1$-functions with zero-boundary values, is not the same as $H^1$. This seems clear to me, but when I tried thinking of a proof for this I had no…
dinosaur
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Is $H^1_0(\Omega)$ dense in $L^2(\Omega)$?

Is $H^1_0(\Omega)$ dense in $L^2(\Omega)$ for bounded domains? It is true for $H^1$ functions of course but what about this subset? Sorry for the elementary question but I never see this so I think the answer is it's not.
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Are Sobolev Spaces Uniformly Convex?

Let $W^{m,p}(\Omega)$ be a Sobolev space, where $\Omega\subset\mathbb{R}^{n}$ is a open set. So the question is: For what $p$ and $m$ the space $W^{m,p}(\Omega)$ is Uniformly Convex. Some reference or the answer would be appreciated.
Tomás
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If $u \in H^1(\Omega) \cap L^\infty(\Omega)$, is $u|_{\partial\Omega} \in L^\infty(\partial\Omega)$?

Let $\Omega$ be a bounded Lipschitz domain. Let $u \in H^1(\Omega) \cap L^\infty(\Omega)$, and suppose that $\lVert u \rVert_{L^\infty(\Omega)} \leq A$. Let $T:H^1(\Omega) \to L^2(\partial\Omega)$ be the trace mapping. Is it true that $Tu \in…
25Chars
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The equivalent definition of $W_0^{1,\infty}(\Omega)$

Usually, for $1\leq p<\infty$, we define $W_0^{1,p}(\Omega)$, where $\Omega$ is open bounded smooth boundary, by taking the closure of $C_c^\infty(\Omega)$ under $W^{1,p}$ norm. However, we don't define $W_0^{1,\infty}(\Omega)$ in the same way since…
spatially
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