Prove that $$\sum_{k=0}^m k x^k = \frac{x(mx^{m+1}-(m+1)x^m +1)}{(x-1)^2}$$
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1Possible duplicate of How can I evaluate $\sum_{n=0}^\infty(n+1)x^n$? – N. F. Taussig May 15 '18 at 20:33