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Prove that $$\sum_{k=0}^m k x^k = \frac{x(mx^{m+1}-(m+1)x^m +1)}{(x-1)^2}$$

Anne Bauval
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Terezia
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2 Answers2

2

HINT :

Can you calculate $$ \sum_{k=0}^{m}x^k ? $$

Atmos
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2

Note that $$\sum_{k=0}^mkx^k=x\frac{d}{dx}\sum_{k=0}^mx^k$$

Andrei
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