I'm currently looking for the proof that a matrix $Q \in \mathbb{K}^{n\times n}$ that is unitary (i.e such that $QQ^*=I)$ is invertible and that $Q^* = Q^{-1}$.
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For square matrices, if $AB=I$, then $BA=I$. – user1551 Mar 08 '18 at 18:40
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A square matrix $A$ is called invertible if there exists $B$ such that $AB=I$, the identity matrix.
Compare this with the equation $QQ^*=I$ and conclude.

lisyarus
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The condition that $Q^* Q= QQ^*= I$ by definition means that this is invertible, with inverse given by $Q^*$.

DKS
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