Questions tagged [partial-derivative]

For questions regarding partial derivatives. The partial derivative of a function of several variables is the derivative of the function with respect to one of those variables, with all others held constant.

The partial derivative of a function of several variables is the derivative of the function with respect to one of the variables, with the others held constant. The partial derivative, like the ordinary derivative, describes the rate of change of a function in a particular direction.

If $f = f(a_1, a_2, \dots, a_n)$ is a function of $n$ variables, then the partial derivative of $f$ with respect to the variable $a_i$ can be written as a limit:

$$\frac{\partial f}{\partial a_i} = \lim_{h \to 0} \frac{f(a_1, \dots, a_i + h, \dots, a_n) - f(a_1, \dots, a_i, \dots, a_n)}{h}.$$

Alternatively, this quantity can be denoted as $f_{a_i}$.

If the function has continuous partial second derivatives, then:

$$\frac{\partial}{\partial x_i}\left(\frac{\partial}{\partial x_j}\right)=\frac{\partial}{\partial x_j}\left(\frac{\partial}{\partial x_i}\right)$$

a result known as Schwarz's Theorem.

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Partial derivative of a composite function

How do I calculate the partial derivative of this composite function $$f(x,y)=\varphi (\frac yx,x^2-y^2,y-x)$$ I don't know the steps I have to take to solve this. Thanks!
Xzya
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Partial derivative and dependent variables

Suppose I have two variables, $a$ and $b$, that are related by $a + b = 1$. This establishes that the only acceptable values of $a$ and $b$ are on a line in the $(a,b)$ plane from $(0,1)$ to $(1,0)$. Consider a function $f(a,b)$. Can we compute the…
Mike H
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Changing order of partial derivatives

Why does $\displaystyle\frac{\partial^2 u}{\partial x \partial y}=\frac{\partial^2 u}{\partial y \partial x}$? Is there a simple proof of this property?
Superbus
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Partial Derivatives: Changing to Polar Coordinates

A function say $f$ of $x$, $y$ is away from the origin. This function can be written in polar coordinates as a function of $r$ and $\theta$. Now, if we know what $\frac{\partial f}{\partial x}$ and $\frac{\partial f}{\partial y}$, how can we find…
Anne
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Intuition behind second total derivative

If we want to find the total derivative of a function $f(x, y)$, we can express it in terms of the function's partial derivatives as follows: $$\frac{df}{dx}=\frac{\partial f}{\partial x}+\frac{\partial f}{\partial y}\frac{dy}{dx}$$ This formula…
David Zhang
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Are partitial differential operators commutative?

I am trying to convert $\Delta=\nabla^2 = \frac{\partial^2}{\partial x^2} + \frac{\partial^2}{\partial y^2}$ to polar coordinates. If anyone has any references on how to do that I would appreciate it. In my evaluation, I am messing with a lot of…
Tsangares
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partial derivative of cosine similarity

I asked a question about derivative of cosine similarity. But no one has answered my question. Therefore I tried to do it my self as…
ycyoon
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Letting $\Delta x\to0$ in multivariable chain rule

In deriving the multivariable chain rule we can start with: $$\Delta u\approx \frac{\partial u}{\partial x} \Delta x +\frac{\partial u}{\partial y} \Delta y$$ and divide both sides by $\Delta t$ say to get: $$\frac{\Delta u}{\Delta t}\approx…
user135842
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Confusion about partial derivatives / the difference between functions and pairs of related variables

If I have a function $f(x,t)=x$, and I also happen to know that $x=t^2$, then the partial derivative $$\frac{\partial f}{\partial t} = 0$$ Now, I get that the idea is 'hold $x$ constant, take the derivative with respect to $t$', but I still keep…
Andrew
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Chain rule for partial derivatives.

Is it true that: $$\frac{1}{2}\frac{d\mu}{dq}\cdot\frac{p^2}{\mu^2}=\frac{1}{2}\frac{d\mu}{dq}\cdot\frac{\partial}{\partial \mu}\left(\frac{-p^2}{2\mu}\right)=-\frac{\partial}{\partial q}\left(\frac{p^2}{2\mu}\right),\;\;\; \mu=\mu(q)$$ And if…
George1811
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Is a reciprocal partial derivative equal to the reciprocal of the partial derivative?

In particular, I have $$\frac{\partial r}{\partial x} = \frac{\partial (x^2 + y^2 + z^2)^{1/2}}{\partial x} = \frac{x}{(x^2 + y^2 + z^2)^{1/2}}= \frac{x}{r}$$ does this mean $$\frac{\partial x}{\partial r} = \frac{r}{x}$$ ? If it is, can we safely…
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Continuity of second partial derivatives: Could $F_{xy}$ be continuous while $F_{yx}$ is not?

THEOREM $3.1$: If $f_{xy}(x, y)$ and $f_{yx}(x, y)$ are continuous on an open set containing $(a, b)$, then $f_{xy}(a, b) = f_{yx}(a, b)$. My question is: Could $F_{xy}$ be continuous while $F_{yx}$ is not? Is there example for this case…
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Symmetry of second (and higher) order partial derivatives

We've learned today that if $f$ has second order partial derivatives that are continuous at some point $a$, then they're all equal to each other at that point. Then there's a short remark that says this holds for higher order as well, i.e.…
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Second partial derivatives equal zero

I have: $$v^2 \frac {\partial^2 f} {\partial x^2} + 2 v \frac {\partial^2 f} {\partial x \partial t} + \frac {\partial^2 f}{\partial t^2} = 0$$ Why does that imply that $\dfrac {\partial^2 f} {\partial x^2} = \dfrac {\partial^2 f} {\partial x…
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Partial Derivatives using ChainRule

Can any one please explain the second step:- Step1: $$\frac{\partial }{\partial x}\left[(1-x^2)\frac{\partial u}{\partial x}\right]+\frac{\partial }{\partial y}\left[y^2\frac{\partial u}{\partial y}\right]=0$$ Step2: $$L.H.S.=-2x\frac{\partial…
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