Questions tagged [holder-inequality]

Proving or manipulations with inequalities by using Hölder's inequality.

  • Let $a_1$, $a_2$,..., $a_n$, $b_1$, $b_2$,..., $b_n$, $\alpha$ and $\beta$ be positive numbers. Prove that: $$(a_1+a_2+...+a_n)^{\alpha}(b_1+b_2+...+b_n)^{\beta}\geq$$$$\geq\left(\left(a_1^{\alpha}b_1^{\beta}\right)^{\frac{1}{\alpha+\beta}}+\left(a_2^{\alpha}b_2^{\beta}\right)^{\frac{1}{\alpha+\beta}}+...+\left(a_n^{\alpha}b_n^{\beta}\right)^{\frac{1}{\alpha+\beta}}\right)^{\alpha+\beta}$$

  • Let $a_{ij}>0$ and $\alpha_i>0$. Prove that: $$\prod_{i=1}^k\left(\sum_{j=1}^na_{ij}\right)^{\alpha_i}\geq\left(\sum_{j=1}^n\left(\prod_{i=1}^ka_{ij}^{\alpha_i}\right)^{\frac{1}{\sum\limits_{i=1}^k\alpha_i}}\right)^{\sum\limits_{i=1}^k\alpha_i}$$

  • Let $f$ and $g$ be positive integrable functions on $[a,b]$ and let $\alpha$ and $\beta$ be positive numbers. Prove that: $$\left(\int\limits_{a}^bf(x)dx\right)^{\alpha}\left(\int\limits_{a}^bg(x)dx\right)^{\beta}\geq\left(\int\limits_{a}^b\left(f(x)^{\alpha}g(x)^{\beta}\right)^{\frac{1}{\alpha+\beta}}dx\right)^{\alpha+\beta}$$

551 questions
8
votes
1 answer

Algebraic significance of Holder conjugates

Consider Holder conjugate exponents $p$ and $q$, i.e., $\frac{1}{p} + \frac{1}{q} = 1$. Multiplying through by $pq$ gives $p + q = pq$. So conjugate exponenets are just those real numbers whose product and sum are the same. I have two questions. Is…
H_R
  • 431
3
votes
1 answer

What is Holder's Inequality?

I have done some research on the internet about the inequality called Holder, but I've encountered some explanations in sites like Turkis Math Wikipedia or Wolfram but none of those explanations were helpful enough, I want to be able to define what…
1
vote
0 answers

Integral version of the Holder Inequality

Hölder Inequality: Let $\left\{a_{1}, a_{2}, \cdots, a_{n} \right\},$ $\left\{b_{1}, b_{2}, \cdots, b_{n}\right\} ,$ $ \cdots\cdots,$ $ \left\{l_{1}, l_{2}, \cdots, l_{n}\right\}$ be $l $ sets of positive real numbers and $\alpha, \beta,…
1
vote
1 answer

Prove Holder inequality by using $a^{\theta}b^{1-\theta}\leq\theta a+(1-\theta)b$ for all $a,b\geq0$ and $\theta\in[0,1]\\$

Known that $a^{\theta}b^{1-\theta}\leq\theta a+(1-\theta)b$ for all $a,b\geq0$ and $\theta\in[0,1]\\$. Now I want to prove, for $x,y\in R^n$ and $p,q>1$ s.t. $\frac{1}{p}+\frac{1}{q}=1$: $\sum_{i=1}^{n}{x_iy_i} \leq…
Walls
  • 75
0
votes
1 answer

Calculating Holder's Inequality for Sums with Exponents

I'm a little confused about the procedure for calculating Holder's Inequalities for Sums with Exponents. For example, I tried to apply Holder's Inequality as follows $$(\sum_{j=1}^{T}p_{j}^{(1/q) + (1/r) - 1})^{q} \leq…
Quinty
  • 3
0
votes
1 answer

Holder inequality for integrals

Using Holder inequality, is it correct to express $$\parallel \int\limits_0^t f(s)g(s)ds \parallel ^p \leq T^{p-1}\int \limits_0^t\parallel f(s)\parallel^pds\int \limits_0^t\parallel g(s)\parallel^pds $$