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Let $f\colon (a,b)\rightarrow \mathbb{R}$ be function. For a non-empty subset $T$ of $(a,b)$, define $\Omega(f,T)=\sup\{|f(x)-f(y)|\colon x,y\in T \}$, and the oscillation function from $(a,b)$ to $\mathbb{R}$ by $x\mapsto \omega_f(x)=\inf\{ \Omega(f,T_x)\}\colon T_x\subseteq (a,b) \mbox{ and } x\in T_x\}$. I couldn't solve few questions about $\omega_f(x)$.

1) Instead of considering all subsets $T_x$ containing $x$, can we consider the sets $B(x,r)\cap (a,b)$, $r>0$, to get the same definition of oscillation function $x\mapsto \omega_f(x)$? In other words, $\inf\{ \Omega(f,T_x)\colon T_x\subseteq (a,b), x\in T_x\} \leq \inf \{\Omega(f,B(x,r)\cap (a,b))\colon r>0 \}$ is clear, but I couldn't prove reverse inequality (if it holds).

2) What can be said about function $x\mapsto \omega_f(x)$? (i.e. is it continuous/ uniformly continuous/ Lipschitz continuous/ differentiable?)


Notation: $B(x,r)=(x-r, x+r)$.

Groups
  • 10,238
  • This is a weird definition of oscillation: Take $f(x)$ to be the characteristic function of the rationals (i.e. $f(x)=1$ if $x\in \mathbb{Q}$ and is zero otherwise), $x=0$ and $T=\mathbb{Q}\cap(-1,1)$ then $\Omega(f,T)=0$ and so $\omega_f(0)=0$. – Jose27 Sep 16 '14 at 03:36
  • Oh! You mean, the definition given by considering $B(x,r)$ instead of $T_x$ is better. – Groups Sep 16 '14 at 04:08
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    Well, the one with balls behaves more like what you'd expect from the oscillation. – Jose27 Sep 16 '14 at 04:32

2 Answers2

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Assuming you've defined "oscillation at a point correctly" (I have not tried to proof-read your definitions), the oscillation function is upper semicontinuous. Thus, you can try googling "oscillation" along with the phrase "upper semicontinuous".

The characteristic function of a Cantor set with positive measure shows that the oscillation function can be discontinuous on a set of positive measure.

On the other hand, because the oscillation function is upper semicontinuous (indeed, being a Baire one function suffices), the oscillation function will be continuous on a co-meager set (i.e. at every point in a set whose complement has first Baire category). Because the set of discontinuities of any function is an $F_{\sigma}$ set, the discontinuities of the oscillation function will be an $F_{\sigma}$ set. Putting the last two results together tells us that the oscillation function always has an $F_{\sigma}$ meager (i.e. first Baire category) discontinuity set. I believe this result is sharp in the sense that given any $F_{\sigma}$ meager set $D,$ there exists a function $f:{\mathbb R} \rightarrow {\mathbb R}$ such that $D$ is equal to the set of all the points at which the oscillation function ${\omega}_{f}$ is not continuous. I don't have time to look into this now, but I believe this sharp result follows from the more precise results proved in [1] and [2] (see also [3]). Regarding what possibilities exist for sets that are $F_{\sigma}$ and meager, see #1-7 in my answer to the math StackExchange question How discontinuous can a derivative be?.

[1] Zbigniew Grande, Quelques remarques sur la semi-continuité supérieure, Fundamenta Mathematicae 126 #1 (1985), 1-13.

[2] Tomasz Natkaniec, On semicontinuity points, Real Analysis Exchange 9 #1 (1983-1984), 215-232.

[3] Janina Ewert, On points of lower and upper semicontinuity of multivalued maps, Mathematical Chronicle 20 (1991), 85-88.

(ADDED NEXT DAY) My conjecture above (where I said I believe this result is sharp in the sense that …) appears to be correct. Indeed, I essentially said as much in this 29 April 2002 sci.math post, where I mentioned that a special case of Theorem 5(a) on p. 561 of [4] (reference below) implies that for each locally bounded non-negative upper semi-continuous function $f:{\mathbb R} \rightarrow {\mathbb R},$ there exists a function $F:{\mathbb R} \rightarrow {\mathbb R}$ such that ${\omega}_{F} = f$. (In analogy with the Fundamental Theorem of Calculus, any such function $F$ is called an ${\omega}$-primitive of $f.)$ It is reasonably well known that any $F_{\sigma}$ meager set can be the discontinuity set for an upper semi-continuous function, and the standard proof of this (see the proof sketch below) gives a function that is also locally bounded and non-negative.

Proof Sketch: Let $D$ be an $F_{\sigma}$ meager subset of ${\mathbb R}.$ Express $D$ as the union of a countable (possibly finite) collection $\{P_n\}$ of closed nowhere dense sets and define $f = \sum \left( 2^{-n}\cdot{\chi}_{P_n}\right),$ where ${\chi}_{P_n}$ is the characteristic function of $P_n$ (i.e. ${\chi}_{P_n}(x) = 1$ if $x \in P_{n},$ and ${\chi}_{P_n}(x) = 0$ if $x \notin P_{n}).$ Then $f$ is a bounded non-negative upper semi-continuous function whose discontinuity set is equal to $D.$

Below are some additional references related to this topic. There are other papers not included, and these can be found by looking for papers by these authors and performing a google phrase search for the title of Kostyrko's paper, "Some properties of oscillation".

[4] Pavel Kostyrko, Some properties of oscillation, Mathematica Slovaca 30 #2 (1980), 157-162.

[5] Zbigniew Duszyński, Zbigniew Jan Grande, and Stanislaw Petrovich Ponomarev, On the $\omega$-primitive, Mathematica Slovaca 51 #4 (2001), 469-476.

[6] Janina Ewert and Stanislaw Petrovich Ponomarev, Oscillation and $\omega$-primitives, Real Analysis Exchange 26 #2 (2000-2001), 687-702.

[7] Cristina Di Bari and Calogero Vetro, Primitive rispetto all'oscillazione [Primitives with respect to oscillation], Rendiconti del Circolo Matematico di Palermo (2) 51 #1 (2002), 175-178.

[8] Janina Ewert and Stanislaw Petrovich Ponomarev, On the existence of $\omega$-primitives on arbitrary metric spaces, Mathematica Slovaca 53 #1 (2003), 51-57.

[9] Stanisław Kowalczyk, On the $\omega$-problem, Real Analysis Exchange Summer Symposium 2011, 120-122.

  • Is there an indication about the connectedness of the set? The example with the fat Cantor set actually demonstrates a totally disconnected set. – user48672 May 18 '17 at 22:28
  • @user48672: The characteristic function of the fat Cantor set is a function from the reals to the reals -- it has the value $1$ at each point in the Cantor set and the value $0$ at each point not in the Cantor set. I believe everything I discussed above is for functions from $\mathbb R$ to $\mathbb R$ (although some of the papers I cited consider more general settings, such as ${\mathbb R}^n,$ metric spaces, etc.). – Dave L. Renfro May 19 '17 at 14:18
  • Incidentally, I realized about a year ago that my "proof sketch" above has a slight flaw --- I think the desired pairwise disjoint decomposition at the beginning of the 2nd sentence is not always possible (if it is possible, then an indication of how to carry this out is probably called for). However, I think the proof doesn't need pairwise disjoint, but I haven't gotten around to carefully looking into this yet. – Dave L. Renfro Sep 14 '20 at 10:25
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You need to require that the set $T_x$ in the definition is an ${\it open}$ neighborhood of x, not just an arbitrary set containing x. Then one can take the open sets to be open balls $B(x,r)$ as you wanted, by the definition of the topology on the real line.

Taking $T_x$ to be an open set containing $x$ allows one to relate oscillation to continuity.

Also, one uses the fact that the $T_x$ are open to show that oscillation is upper semi-continuous.