What are the best known asymptotics for the nth zeta zero (imaginary part)? Is there anything similar to $p_n\sim n\log n$, ie where $\rho$ is in form $\sigma+it$, $t_n\sim\dots?$
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Guilherme França, André LeClair: http://i.stack.imgur.com/CmZmV.png – Mats Granvik Jul 17 '15 at 10:51
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Table[N[InverseFunction[RiemannSiegelTheta][Pi*(n - 1/2)], 30], {n, 0, 12}] – Mats Granvik Apr 21 '19 at 09:50
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Related thread1 and thread2 – Raymond Manzoni Apr 15 '22 at 11:37
2 Answers
Yes, $\gamma_n\sim2\pi n/\log(n)$. This is in Titchmarsh, for example.
For a better asymptotic, write the number of zeros to height $T$ as $$ N(T)\sim \frac{T}{2\pi}\log\left(\frac{T}{2\pi}\right)-\frac{T}{2\pi}. $$ (The error term in this asymptotic is $O(\log(T))$.) We want to invert the relationship $$ n \sim \frac{\gamma_n}{2\pi}\log\left(\frac{\gamma_n}{2\pi}\right)-\frac{\gamma_n}{2\pi}. $$ Mathematica tells me that $$ \gamma_n\sim \frac{2\pi n}{W(n/e)}, $$ where $W(z)$ is the Lambert function, which inverts $z=w\exp(w)$. ($W(z)$ is called ProductLog in Mathematica)
A better asymptotic would require a better one for $N(T)$, which depends subtly on $S(T)$, the argument of the Riemann zeta function.

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@Partey5 The Argument Principle in complex analysis, the functional equation for the zeta function, and Stirling's formula asymptotic for the Gamma function which appears in the functional equation. – stopple Oct 29 '21 at 20:31
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You may check following paper:
A theory for the zeros of Riemann Zeta and other L-functions by Guilherme França, André LeClair

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