Given $a,b,n \in \mathbb N$, prove that $a-b|a^n-b^n$. I think about induction. The assertion is obviously true for $n=1$. If I assume that assertive is true for a given $k \in \mathbb N$, i.e.: $a-b|a^k-b^k$, I should be able to find that $a-b|a^{k+1}-b^{k+1}$, but I can't do it. Any help is welcome. Thanks!
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2http://math.stackexchange.com/questions/188657/why-an-bn-is-divisible-by-a-b – lab bhattacharjee Nov 25 '13 at 17:12
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Rankeya's answer addresses what is asked here. – leo Nov 25 '13 at 17:16
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The assertion is even moreobviously true for $n=0$, by the way :) – Hagen von Eitzen Nov 25 '13 at 17:32
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To complete the induction, note that
$a^{k + 1} - b^{k + 1} = a^{k + 1} - a^kb + a^kb - b^{k + 1} = a^k(a - b) + b(a^k - b^k), \tag{1}$
then simply observe that
$(a - b) \mid a^k(a - b), \tag{2}$
which is obvious, and that
$(a - b) \mid (a^k -b^k) \tag{3}$
by the induction hypothesis
$(a - b) \mid (a^k - b^k). \tag{4}$
Since $a - b$ divides both summands, it divides their sum.QED
Hope this helps. Cheerio,
and as always,
Fiat Lux!!!

Robert Lewis
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@ Walter: my pleasure, glad to be of service. And thanks for your "acceptance"! I'm sorry to see your question was closed (not my doing, by the way), but I guess it has been asked before on MSE. Best Regards, Robert Kenneth Lewis – Robert Lewis Nov 25 '13 at 18:17