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On a test I got a question asking to simplify $\sqrt{-25}\times \sqrt{-3}$

I answered $5\sqrt 3$ but apparently it's only $-5\sqrt 3$ because of some rule of imaginary numbers, could someone please explain to me why $\sqrt{-25}\times \sqrt{-3} \ne \pm 5\sqrt 3$

player3236
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Dalton
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1 Answers1

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You presumably tried to use the "rule" $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$. However, this only holds when $a$ and $b$ are positive! It is not applicable here.

Instead, we need to compute this product directly. $\sqrt{-25} = 5i$ and $\sqrt{-3} = i\sqrt{3}$, so $$\sqrt{-25} \sqrt{-3} = (5i)(i \sqrt{3}) = -5\sqrt{3}.$$

  • But −5√3̅ = -5√̅1̅̅3̅ and the √1̅ = ±1 if we use the √1̅ = -1 and we can then say that 5√̅1̅̅3̅ = -5√̅(̅-̅1̅)̅(̅-̅1̅)̅*̅3̅ then we can either take out the -1's to get -(-1)5√̅3̅ or we can turn the -1's to i² and take them out to get i²5√̅3̅ both of which are equal – Dalton Feb 12 '21 at 19:41
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    @Dalton $\sqrt{1}$ denotes the positive square root of $1$, not both of them. The square roots of $1$ are $\pm \sqrt{1}$. It's not the case that $\sqrt{1}=\pm 1$. – MHW Feb 12 '21 at 20:03