The equation y(x)=sin(kx) where x needs to be the subject
Note:y function of x not y times x
What I did is x=1/ksin^-1(y(x)) However, x is still on the right-hand side. How should I approach this further? Any suggestions?
The equation y(x)=sin(kx) where x needs to be the subject
Note:y function of x not y times x
What I did is x=1/ksin^-1(y(x)) However, x is still on the right-hand side. How should I approach this further? Any suggestions?
Assuming that the equation to be solved is $$x \times y=\sin(k x)$$ there is no analytical solutions and numerical methods are required. We can make more or less accurate approximations .
To simplify the problem, let $kx=t$ and $a=\frac t k$ making the equation $$\sin(t)=a t\qquad \text{with} \qquad 0 < a < 1$$
If I may suggest, have a look at this question of mine where the problem has been quite extensively discussed.