From taking an undergraduate Real Analysis course, I believe the answer depends on what kind of space our sequence is in.
If we're in a metric space, I believe this can be more complicated and a limit point is NOT the same thing as an accumulation point. I think there is at least one distinction between a limit point and an accumulation point inside of metric spaces, namely that they both describe conditions for a different number of distinct, other points inside neighborhoods or balls around the limit/accumulation point.
If we had a neighborhood around the point we're considering (say $x$), a limit point's neighborhood would be contain $x$ but not necessarily other points of a sequence in the space, but an accumulation point would have infinitely many more sequence members, distinct, inside this neighborhood as well aside from just the limit point. In other words, accumulation points describe a "build up" of similar, distinct points nearby and not just the convergence trend of a sequence of points (inside a metric space, anyway).
Some set theory notation describing what I think the difference is for some sequence of points in a subset $E$ of the metric space $\{x_n\}$ that converges to $x$ (assuming $x$ is also in $E$ and we're simply using $\varepsilon > 0$ as our all radius, and using $d$ as our metric space function):
An open ball around $x$ as a limit point would mean:
$$B_\varepsilon(x, d)\cap E≠\varnothing$$
An open ball around $x$ as an accumulation point would mean:
$$B_\varepsilon(x, d)\setminus\{x\}\cap E≠\varnothing$$
Relevance of Distinction
As far as I know, the relevance is that in metric spaces, not all Cauchy sequences are convergent -- all Cauchy sequences being convergent means a metric space is "complete", which is a property related to "compact", i.e., the differences between the types of convergence points can be used to help illustrate what sorts of sequences in a given space we have and whether or not it is Cauchy or convergent.
Hope this helps!