Possible Duplicate:
“Closed” form for $\sum \frac{1}{n^n}$
\begin{equation} \sum^ {\infty} _{n=1} {\frac{1}{n^n}} \end{equation}
I have tried a lot, but can't find the solution.
Thanks in advance.
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10See it – Hanul Jeon Jan 25 '13 at 07:04
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$$\sum^ {\infty} {n=1} {\frac{1}{n^n}}=\int{0}^1 \frac{1}{x^x} dx$$ – Ethan Splaver Jan 25 '13 at 07:20
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1Haha... ‘Dream it’ sounds good too. – Haskell Curry Jan 25 '13 at 07:24
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Ahhh this brings back memories. – Euler....IS_ALIVE Jan 25 '13 at 07:28
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2Is this the answer? The left hand side looks as solved to me as the right hand side. – Fabian Jan 25 '13 at 07:42
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1I agree with @Fabian: how is the LHS more "computed" after it is written as the RHS, than before? And what does "compute" mean here? – Did Jan 25 '13 at 07:55
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I thought the series converge to certain number like $\frac{{\pi}^2}{6}$ before asking a question. – Jan 25 '13 at 08:07
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@YongRyu Certainly the value is less than that. – AD - Stop Putin - Jan 25 '13 at 08:09
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1Can someone explain to me why @Arjang suggested deleting the link to the duplicate question, and why Henry and Brett approved it? I understand these suggested edits less and less every day. – Jan 26 '13 at 01:19
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@RahulNarain : I did not suggest deleting the link, the title was too broad and I made it specific. I just rolled back the role back that was making the title too generic. – jimjim Jan 26 '13 at 01:28
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1@Arjang: When you roll back to an older version, you remove all the changes that have happened since, including in this case the insertion of the "Possible Duplicate:" link. – Jan 26 '13 at 01:33
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@RahulNarain : Apologies in that case, the version I submitted was rolled back and I failed to notice the other changes, duely noted – jimjim Jan 26 '13 at 03:27