Can anyone help to find a formula for this?
$$\sum_{k=1}^n\frac{k}{(1+r)^k}=\frac{1}{1+r}+\frac{2}{(1+r)^2}+\frac{3}{(1+r)^3}+\cdots+\frac{n}{(1+r)^n}.$$
I cannot seem to use $\dfrac{n(n+1)}{2}$ in anyway.
Can anyone help to find a formula for this?
$$\sum_{k=1}^n\frac{k}{(1+r)^k}=\frac{1}{1+r}+\frac{2}{(1+r)^2}+\frac{3}{(1+r)^3}+\cdots+\frac{n}{(1+r)^n}.$$
I cannot seem to use $\dfrac{n(n+1)}{2}$ in anyway.
cauchy-integral-formula
. – José Carlos Santos May 27 '18 at 06:46