Is it true $tr(\mu\mu^{T}A) = \mu^{T}A\mu$, where $\mu$ is vector of opropriate order?
I verified it for $3\times3$ case.
Is it true $tr(\mu\mu^{T}A) = \mu^{T}A\mu$, where $\mu$ is vector of opropriate order?
I verified it for $3\times3$ case.
Yes. In general, regardless of the sizes of the matrices $X$ and $Y$, if $XY$ and $YX$ are legitimate matrix multiplications, then the two matrix products have the same nonzero eigenvalues and hence the same traces.