A friend of mine is studying biology, and in a project of hers, she had to measure the beak (and other parts of the body) of some dozens of birds of a same specie, and analyze the data. In particular, she found out (as it was supposed) that the distribution of the lengths of the beaks is close to a normal distribution. I wonder why that happens.
The central limit theorem states that
If $X_1,...,X_n$ are independent and identically distributed random variables and have the same mean $\mu$ and variance $\sigma^2$, then the distribution of $$ \frac{X_1+...+X_n}{n} $$ converges to $$ N(\mu,\sigma^2)=\frac{1}{\sqrt{2\pi\sigma^2}}e^{-\frac{(x-\mu)^2}{2\sigma^2}} $$ as $n\rightarrow\infty$.
We also know that $X_1+...+X_n$ itself also has a normal distribution. So, by the "why" above, I simply mean: "what are these $X_1,...,X_n$?".
My thoughts:
Let us say that all the birds of the given specie are born with a beak of the same length $a$. This seems to me to be approximately true. Also, let us say that the beaks of these birds stop growing when they are $b$ years hold, and that all measured birds are older than that (so all of them have full-grown beaks). I would say that this models the conditions of the measurement pretty well. Now, each day that passes, the beak of a given bird grows a little bit. Here is the key point: the amount that it grows is given by a certain (unknown) probability distribution, which is the same for all birds and at all times $t<b$. We now set $n$ to be the number of days in $b$ years, and $X_i$ is the beak growth in day $i$. With this model in mind, we see that the beak length of a bird is simply $X_1+...+X_n$ and we know that this follows a normal distribution.
Any comments on my model?
Another case
And what about IQ distribution, for example? Can it be a "growth process" like this one, but with things other than beak length?