The natural numbers are the prime model of PA: in a precise sense, they are the least rich model. There are lots of notions of richness of models; these are usually expressed in terms of the realized types, essentially what sort of behavior occurs in the model. E.g. the natural numbers are not very rich since "is divisible by $2$ and $3$ and $5$ and ..." is a very easily-describable behavior which is not realized in $\mathbb{N}$.
As to whether $\mathbb{N}$ is nonstandard in any sense: certainly not in the sense that we use the word when speaking of nonstandard models. Since $\mathbb{N}$ is the smallest model of PA, there's no way to shrink it further and still have a model of PA.
Incidentally, there's an interesting set-theoretic difficulty here: conceivably the thing we think is $\mathbb{N}$ could actually be a very clever nonstandard model. This has been investigated by a number of mathematicians and philosophers, and has had lots of discussion on this site (see e.g. this question). But that wouldn't mean "$\mathbb{N}$ is nonstandard," that would mean "we were wrong about what $\mathbb{N}$ is" - $\mathbb{N}$ is defined as the smallest thing it could be (this can be made completely precise via second-order logic (this question says a bit about that), but since second-order logic is intimately bound up in set theory this isn't entirely satisfying).