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I have encountered the puzzling fact (just right here on MSE twice: here and here) that the union of intervals of positive length around rational numbers do not cover the real line.

Consider an ordering of the rational numbers $\{r_n\}$ and the intervals belonging to each of them

$$I_n=(r_n-q^{-n},r_n+q^{-n}), \ \ q>3, \ \ n=1,2,\dots$$

The Lebesgue measure of the union of these intervals is surprisingly small:

$$\lambda\left(\bigcup_{n=1}^{\infty}I_n\right)\le\sum_{n=1}^{\infty}\lambda(I_n)=2\sum_{n=1}^{\infty}q^{-n}=\frac{2}{q-1}<1.$$

That is, the union above does not even cover $[0,1]$. So, there are real numbers in the unit interval that are not covered by the union in question. Clearly, the set of the missing reals depend on the ordering we use. OK. But let's take, as an example, the well known classical ordering.

Could anybody point at (construct) an actual real number not in the union belonging to the ordering mentioned?

zoli
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