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I want to simplify $wxy + x'z + y'z + wz = wxy + x'z + y'z$ but I can't seem to use the consensus theorem at the right place.

I tried factoring cases for $x$ and $x'$ and $y$ and $y'$ but I don't know where to go. Can anyone give me just a hint (not the full answer)?

maregor
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1 Answers1

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Write

$$wxy+x'z+y'z+wz=wxy+(x'+y')z+wz=(xy)w+(xy)'z+wz$$

using distributive and De Morgan laws, and then apply the consensus theorem as stated here with $X=xy$, $Y=w$, and $Z=z$.

Community
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Brian M. Scott
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