Possible Duplicate:
Prove by induction
I am stuck with my maths assignment. I need to prove for all integers $n\geq 1$
$$\sum_{i=1}^{n}(3i-1)^2=\frac{1}{2}n(6n^2+3n-1)\;.$$
Possible Duplicate:
Prove by induction
I am stuck with my maths assignment. I need to prove for all integers $n\geq 1$
$$\sum_{i=1}^{n}(3i-1)^2=\frac{1}{2}n(6n^2+3n-1)\;.$$