What type of isomers are the following two compounds?They do not seem to be geometrical isomers as the methyl groups at terminal position are not in same plane as such.Are they conformers?
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1Believe it or not, they are enantiomers. Oh, and you don't normally draw them like that, because like you said, those methyls are out of plane. – Ivan Neretin Aug 10 '16 at 05:44
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Could you explain a bit more elaborately if you have time?Thanks. @IvanNeretin – Aug 10 '16 at 05:47
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@IvanNeretin I did'nt draw them :-P! – Aug 10 '16 at 05:48
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Then these pictures are meaningless and don't represent anything. Or, if we put it another way, they are poorly drawn pictures of the same compound (like in @julien's answer), which, BTW, exists as a pair of enantiomers, but the pictures don't tell you which is which. – Ivan Neretin Aug 10 '16 at 05:50
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@IvanNeretin Oh well I think I understood why they are enantiomers! – Aug 10 '16 at 05:51
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Related: Why are allenes chiral? and How are the Cahn-Ingold-Prelog rules applied to chiral molecules without a stereogenic carbon center? i.e biphenyls and allenes – Aug 10 '16 at 11:42
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It is easier to visualise if you draw, for example, the methyl and the hydrogen on the left in the plane of the paper, then the methyl and hydrogen on the right, are at right angles to this and so in and out of the plane. – porphyrin Aug 10 '16 at 13:19
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@Sanc Are you sure, though, that those questions are unrelated? Perhaps they're very relevant and you just stopped someone from helping you. – M.A.R. Aug 11 '16 at 07:49
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@TIPS I'm sorry. – Aug 11 '16 at 07:52