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I thought I had it figured out, but it appears that my regex still has quirks in it. Basically I would like to use the same regex pattern to match the following major email clients (Gmail, Yahoo, and regular email):

"Brian Mang" <[email protected]>   -- Case1
Brian Mang ([email protected])     -- Case2
<[email protected]>                -- Case3
[email protected]                  -- Case4

I had the following regex pattern: 

/[\W"]*(?<name>.*?)[\"]*?\s*[<(](?<email>\w.*)[>)]/.match(contact)

and it works for all Cases 1-3, but I cant get it to pick up case 4, I tried messing around with it but cant figure it out cause it breaks the other cases. Any idea what I need to change/modify to make my regex pick up all of the 4 cases? Thank you.

Michael Berkowski
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Kamilski81
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2 Answers2

2

Try this

[\W"]*(?<name>.*?)[\"]*?\s*[<(]?(?<email>\S+@\S+)[>)]?

See it here on Regexr

I made the classes surrounding the address optional and changed the part that matches the email to \S+@\S+ that means at least one non-whitespace followed by a @ then at least one more non-whitespace character.

Since the above version matches the closing character also, you can restrict the part after the @ a bit more

[\W"]*(?<name>.*?)[\"]*?\s*[<(]?(?<email>\S+@[^\s>)]+)[>)]?

see it here on Regexr

stema
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  • Thanks @stema but it appears that the final puncuation >) still exist for Case1 & Case2 & Case4., for example: email [email protected]> has the punctuation at the end, i tried messing with it but cant figure out how to remove it? – Kamilski81 Feb 11 '12 at 23:36
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Edit: This one works for all four:

[\W"]*(?<name>.*?)[\"]*?\s*[<(]?(?<email>\S+@[^)>]+)[>)]?
user2398029
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