Extract email from string

Question

I have a string as:

string="""Recipient:
[email protected] \--- mail_boundary --- ATTENTION: This email came from an
external source.

Sender: [email protected] Subject: [External] *LEGALZOOM OPENS AT $30, IPO
AT $28 Message-Id: <60DC94E60001AE8432F70080_0_2129298@mscv03>
Recipient: [email protected] \--- mail_boundary --- """

All I want to extract the email-ID's corresponding to keyword Recipient: i.e. email_id=['[email protected]','[email protected]']

What I have tried as:

email_id=re.findall(r'Recipient: (.+)',string)

refer here:https://stackoverflow.com/questions/17681670/extract-email-sub-strings-from-large-document/17681902 — gretal, Dec 08 '21 at 07:00
@gretal Already checked. It gives all the email ID's in string. I want only those which is corresponding to keyword `Recipient:` — Learner, Dec 08 '21 at 07:31
Then just replace the `(.+)` from your pattern with what they give as a valid email pattern — Tomerikoo, Jan 31 '23 at 14:53

score 0 · Answer 1 · answered Dec 08 '21 at 08:16

You can use

re.findall(r'\bRecipient:\s*(\S+@\S+)', text)

See the regex demo. Details:

\b - word boundary
Recipient: - a fixed string
\s* - zero or more whitespaces
(\S+@\S+) - Group 1: one or more non-whitespace chars, @ and one or more non-whitespace chars

See the Python demo:

import re
text = """Recipient:
[email protected] \--- mail_boundary --- ATTENTION: This email came from an
external source.
 
Sender: [email protected] Subject: [External] *LEGALZOOM OPENS AT $30, IPO
AT $28 Message-Id: <60DC94E60001AE8432F70080_0_2129298@mscv03>
Recipient: [email protected] \--- mail_boundary --- """
 
print( re.findall(r'\bRecipient:\s*(\S+@\S+)', text) )
# => ['[email protected]', '[email protected]']

Extract email from string

1 Answers1