5

I try to send mails from python to multiple email-addresses, imported from a .txt file, I've tried differend syntaxes, but nothing would work...

The code:

s.sendmail('[email protected]', ['[email protected]', '[email protected]', '[email protected]'], msg.as_string())

So I tried this to import the recipient-addresses from a .txt file:

urlFile = open("mailList.txt", "r+")
mailList = urlFile.read()
s.sendmail('[email protected]', mailList, msg.as_string())

The mainList.txt contains: 

['[email protected]', '[email protected]', '[email protected]']

But it doesn't work...

I've also tried to do:

... [mailList] ... in the code, and '...','...','...' in the .txt file, but also no effect

and

... [mailList] ... in the code, and ...','...','... in the .txt file, but also no effect...

Does anyone knows what to do?

Thanks a lot!

AnFi
  • 10,493
  • 3
  • 23
  • 47
Francis Michels
  • 117
  • 1
  • 3
  • 7

6 Answers6

35

This question has sort of been answered, but not fully. The issue for me is that "To:" header wants the emails as a string, and the sendmail function wants it in a list structure.

# list of emails
emails = ["[email protected]", "[email protected]", "[email protected]"]

# Use a string for the To: header
msg['To'] = ', '.join( emails )

# Use a list for sendmail function
s.sendmail(from_email, emails, msg.as_string() )
Banjer
  • 8,118
  • 5
  • 46
  • 61
3
urlFile = open("mailList.txt", "r+")
mailList = [i.strip() for i in urlFile.readlines()]

and put each recipient on its own line (i.e. separate with a line break).

pyroscope
  • 4,120
  • 1
  • 18
  • 13
2

The sendmail function requires a list of addresses, you are passing it a string.

If the addresses within the file are formatted as you say, you could use eval() to convert it into a list.

Acorn
  • 49,061
  • 27
  • 133
  • 172
2

It needs to be a real list. So, with this in the file:

[email protected],[email protected],[email protected]

you can do

mailList = urlFile.read().split(',')
Daniel Roseman
  • 588,541
  • 66
  • 880
  • 895
1

to_addrs in the sendmail function call is actually a dictionary of all the recipients (to, cc, bcc) and not just to.

While providing all the recipients in the functional call, you also need to send a list of same recipients in the msg as a comma separated string format for each types of recipients. (to,cc,bcc). But you can do this easily but maintaing either separate lists and combining into string or convert strings into lists.

Here are the examples

TO = "[email protected],[email protected]"
CC = "[email protected],[email protected]"
msg['To'] = TO
msg['CC'] = CC
s.sendmail(from_email, TO.split(',') + CC.split(','), msg.as_string())

or

TO = ['[email protected]','[email protected]']
CC = ['[email protected]','[email protected]']
msg['To'] = ",".join(To)
msg['CC'] = ",".join(CC)
s.sendmail(from_email, TO+CC, msg.as_string())
lishikawa
  • 11
  • 1
0
urlFile = open("mailList.txt", "r")

list=[]        #create an empty list

for line in urlFile.readlines():
    x=line.strip()
    list.append(x)

print(list)
Umair Basharat
  • 1
  • 1
    Thank you for contributing to the Stack Overflow community. This may be a correct answer, but it’d be really useful to provide additional explanation of your code so developers can understand your reasoning. This is especially useful for new developers who aren’t as familiar with the syntax or struggling to understand the concepts. **Would you kindly [edit] your answer to include additional details for the benefit of the community?** – Jeremy Caney Aug 17 '23 at 02:07