Is there a way to delete characters after @ in an email address?

Question

I am trying to delete characters after "@" in an email address using python. I found some tips online but it didn't provide the exact solution I am looking for.

The whole email address I'm working on is coming from a parameter value.

paramater = [0]  #contains the email address i.e. [email protected]
mainStr = parameter [0]
newstring = mainStr.replace('@' , ' ')

Obviously, the above code is not providing me with result I am expecting which is to delete all strings after @.

I learned a tip a while back. If you are printing an array to the console, and you want to delete unnecessary values, then don't delete them, just don't print them. You don't have to delete the characters after `@`, just don't print them. — , Sep 11 '19 at 00:57

Derek Eden · Answer 1 · 2019-09-11T01:57:11.907

2

in = '[email protected]'
out = s.split('@')[0]

or

out = ''.join(re.findall('(.*)@',s))

edited Sep 11 '19 at 01:57

answered Sep 11 '19 at 01:04

Derek Eden

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You can do `s.split('@', 1)[0]`, it _would_ be even faster. – geckos Sep 11 '19 at 01:39
this is true..but since OP is about email addresses, there will only be one split – Derek Eden Sep 11 '19 at 01:41
In fact `.split(..., 1)` was slower ¯\\_(ツ)_/¯ – geckos Sep 11 '19 at 01:45
>>> timeit('"[email protected]".split("@", 1)[0]') 0.20608205100143095 >>> timeit('"[email protected]".split("@")[0]') 0.20366473000467522 – geckos Sep 11 '19 at 01:45
XD weird .. thought you wouldve been right – Derek Eden Sep 11 '19 at 01:46
Me too :D, maybe an obscure optimization is taking place – geckos Sep 11 '19 at 01:47

score 1 · Answer 2 · answered Sep 11 '19 at 01:37

1

With regex

import re
re.sub(r'@.*', '', '[email protected]')

answered Sep 11 '19 at 01:37

geckos

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was hoping someone would bust out the regex – Derek Eden Sep 11 '19 at 01:38

score 0 · Answer 3 · answered Sep 11 '19 at 01:01

0

I don't know your code. But, I write code by my way.

s = [email protected]
end = s.find('@')
s[:end]

answered Sep 11 '19 at 01:01

Yeonsik Choi

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Rephrase your answer to capture what you mean, s = '[email protected]' and there should be a print statement at the end of your code block. – oriohac Mar 30 '23 at 06:45

score 0 · Answer 4 · answered Sep 11 '19 at 01:06

0

Do you want a part of account? ( for example " testing" in "[email protected]")

Then

exampleString = "[email protected]"
indexOfAt = exampleString.find("@") # get index of @
print (indexOfAt)
accountPart = exampleString[:indexOfAt]
print (accountPart)

the result is as follows

7
testing

answered Sep 11 '19 at 01:06

김종명

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exact copy of other solution – Derek Eden Sep 11 '19 at 01:38

Is there a way to delete characters after @ in an email address?

4 Answers4