Array of objects return object when condition matched

Question

I have an array which have value of id, email and password.

let array = [
 {id: hyu, email: [email protected], password: 123},
 {id: rft, email: [email protected], password: 456},
 {id: ght, email: [email protected], password: 789},
 {id: kui, email: [email protected], password: 679}
]

Now I would like to return that object when my condition is matched. For that I created a function using javascript some function but I want to return the object and we know that some function return boolean.

I don't have any idea how to do this.

My code is:

const isEmailExists = (email, array) => {
  return array.some(function(el) {
    return el.email === email;
  });
};

if (isEmailExists("[email protected]", array) == true) {
  // I want to work here with returned objects i.e on success case
} else {
  // error case
}

Any help is really appreciated

Possible duplicate of [Javascript: How to filter object array based on attributes?](https://stackoverflow.com/questions/2722159/javascript-how-to-filter-object-array-based-on-attributes) — Shibon, Apr 03 '19 at 09:12

Sebastian Kaczmarek · Accepted Answer · 2019-04-03T10:26:04.963

12

You can make use of .filter() and check if the filtered array has a length of more than 0:

let array = [
 {id: 'hyu', email: '[email protected]', password: 123},
 {id: 'rft', email: '[email protected]', password: 456},
 {id: 'ght', email: '[email protected]', password: 789},
 {id: 'kui', email: '[email protected]', password: 679}
]

let filtered = array.filter(row => row.email === '[email protected]');

console.log(filtered);

if (filtered.length > 0) { /* mail exists */ }
else { /* mail does not exist */ }

edited Apr 03 '19 at 10:26

answered Apr 03 '19 at 09:08

Sebastian Kaczmarek

8,120
4
20
38

what if we have to make a list of array object and have more conditions? suppose in an array object I need to filter those element whose "name" has "John", "Mark", & "Kevin" and create another array object of only these 3 people, how to achieve this? – Mohit Jan 22 '23 at 12:45
You can change the callback function in `filter()` to something like this: `array.filter(row => ["John", "Mark", "Kevin"].includes(row.name));` – Sebastian Kaczmarek Feb 07 '23 at 13:10

score 12 · Answer 2 · answered Apr 03 '19 at 09:10

Assuming the email is unique, you can use find(). This will return null if not email does not exist.

let array = [{"id":"hyu","email":"[email protected]","password":123},{"id":"rft","email":"[email protected]","password":456},{"id":"ght","email":"[email protected]","password":789},{"id":"kui","email":"[email protected]","password":679}];

const getObject = (email, array) => {
  return array.find(function(el) {
    return el.email === email;
  }) || null;
};

console.log(getObject("[email protected]", array));

Shorter Version:

const getObject = (email, array) => array.find(el => el.email === email ) || null;

score 2 · Answer 3 · answered Apr 03 '19 at 12:32

Use find(), not filter(), when you expect zero or one match. find() will return undefined if no match is found and since undefined is falsy and any object is truthy, you can use the return value as a condition for an if clause directly.

const array = [
 {id: 'hyu', email: '[email protected]', password: 123},
 {id: 'rft', email: '[email protected]', password: 456},
 {id: 'ght', email: '[email protected]', password: 789},
 {id: 'kui', email: '[email protected]', password: 679}
]

const mail = array.find(row => row.email === '[email protected]');

if (mail) {
  // Do stuff with mail
  console.log(mail);
} else {
  // Handle error
}

score 0 · Answer 4 · answered Apr 03 '19 at 09:09

You could take a function and hand over the key and the value and filter the array.

function getObjects(array, key, value) {
    return array.filter(object => object[key] === value);
}

let array = [{ id: 'hyu', email: '[email protected]', password: 123 }, { id: 'rft', email: '[email protected]', password: 456 }, { id: 'ght', email: '[email protected]', password: 789 }, { id: 'kui', email: '[email protected]', password: 679 }];

console.log(getObjects(array, 'email', '[email protected]'));

score 0 · Answer 5 · answered Apr 03 '19 at 11:02

0

const found = array.find(item => (item.email === '[email protected]')) || null;
console.log(found);

answered Apr 03 '19 at 11:02

unnamed-bull

361
4
15

Array of objects return object when condition matched

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