awk or sed extract each number of column alone

Question

Hello i want to extract each line count to a file by command.

4495125 94307025    [email protected]   94307025.094307025  12443
stazla  [email protected]  1992/.:\1
1447585 [email protected] h1st@1
saknit  [email protected]   1233    1990
_______________________________________________________
5column.txt
4495125 94307025    [email protected]   94307025.094307025  12443
_______________________________________________________
4column.txt 
saknit  [email protected]   1233    1990
_______________________________________________________
3column.txt 
stazla  [email protected]  1992/.:\1
1447585 [email protected] h1st@1

i need code to do this job please!!

Please show us what you have tried so far. We need to see the effort. — dmitryro, Jan 02 '18 at 04:11
dmitryro i have tested with simple script awk -F : -v OFS=':' '{print $1, $2, $3}' — Smart Josef, Jan 02 '18 at 04:13
can you explain why you used the field separators? your given sample doesn't seem to need it.. — Sundeep, Jan 02 '18 at 04:15
hint: use `NF` to form file name and see https://www.gnu.org/software/gawk/manual/html_node/Redirection.html for redirecting print output... — Sundeep, Jan 02 '18 at 04:17
You don't even explain what "each line count" is; we can guess but this is far from clear. — vaettchen, Jan 02 '18 at 05:51
The test data is suspiciously similar to https://stackoverflow.com/questions/48056103/set-an-external-variable-in-awk — tripleee, Jan 02 '18 at 06:17

score 0 · Accepted Answer · answered Jan 02 '18 at 05:49

0

Following awk could help you in same.

awk '{print > NF"column.txt"}'  Input_file

Output it will create 3 files named 5column.txt, 4column.txt and 3column.txt.

answered Jan 02 '18 at 05:49

RavinderSingh13

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awk or sed extract each number of column alone

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