send email using python using Gmail

Question

I have written a python script to send email from my gmail account to my another email. the code is:

import smtplib
fromaddr = '[email protected]'
toaddrs  = '[email protected]'

msg = 'my message'

username = '[email protected]'
password = 'myPass'

server = smtplib.SMTP('smtp.gmail.com:587')
server.ehlo()
server.starttls()
server.login(username,password)
server.sendmail(fromaddr, toaddrs, msg)
server.quit()
print("Done")

I'm also getting the "Done" output as the email is being sent. But the problem is: I can't seem to receive the email. It doesn't show up in the inbox. I can't find the problem :( Can anyone please help?

Thanks in advance...

Depends on what OS you are on, it might have restrictions on port 587. — , Apr 27 '17 at 20:00
RIght now I've logged in to my [email protected] to see if the email has been sent. Email was sent & in reply I got this email, "Your message to [email protected] has been blocked. See technical details below for more information. LEARN MORE" — yohowi, Apr 27 '17 at 20:03
Possible Dup: https://stackoverflow.com/questions/10147455/how-to-send-an-email-with-gmail-as-provider-using-python — Pedro Lobito, Apr 27 '17 at 20:16
It could help to tell us what where the *technical details*... — Serge Ballesta, May 02 '17 at 07:54

Moolshanker Kothari · Answer 1 · 2017-05-02T08:13:29.457

Check this out, this works for me perfectly...

def send_mail(self):
    import smtplib
    from email.MIMEMultipart import MIMEMultipart
    from email.MIMEText import MIMEText

    gmailUser = '[email protected]'
    gmailPassword = 'P@ssw0rd'
    recipient = '[email protected]'
    message='your message here '

    msg = MIMEMultipart()
    msg['From'] = gmailUser
    msg['To'] = recipient
    msg['Subject'] = "Subject of the email"
    msg.attach(MIMEText(message))

    mailServer = smtplib.SMTP('smtp.gmail.com', 587)
    mailServer.ehlo()
    mailServer.starttls()
    mailServer.ehlo()
    mailServer.login(gmailUser, gmailPassword)
    mailServer.sendmail(gmailUser, recipient, msg.as_string())
    mailServer.close()

Should be `from email.mime.multipart import MIMEMultipart` & `from email.mime.text import MIMEText` and the self parameter is superfluous — Zander Brown, Jul 17 '17 at 16:53

score 0 · Answer 2 · answered Feb 27 '20 at 16:05

Enable less secure apps on your gmail account and for Python3 use:

import smtplib
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText

gmailUser = '[email protected]'
gmailPassword = 'XXXXX'
recipient = '[email protected]'

message = f"""
Your message here...
"""

msg = MIMEMultipart()
msg['From'] = f'"Your Name" <{gmailUser}>'
msg['To'] = recipient
msg['Subject'] = "Your Subject..."
msg.attach(MIMEText(message))

try:
    mailServer = smtplib.SMTP('smtp.gmail.com', 587)
    mailServer.ehlo()
    mailServer.starttls()
    mailServer.ehlo()
    mailServer.login(gmailUser, gmailPassword)
    mailServer.sendmail(gmailUser, recipient, msg.as_string())
    mailServer.close()
    print ('Email sent!')
except:
    print ('Something went wrong...')

send email using python using Gmail

2 Answers2