Print the current number of item in a cycle for x in y

Question

I have this script:

accounts = open("accounts.txt").readlines()

y = [x.strip().split(":") for x in accounts]

for account in y:
    print ("Trying with: %s:%s" % (account[0], account[1]))

the file accounts.txt is structred like this:

[email protected]:test1
[email protected]:test2
[email protected]:test3

How can i add to the print "Trying with... bla bla" the current line of the account? An output like:

Trying with: [email protected]:test1 @1
Trying with: [email protected]:test1 @2
Trying with: [email protected]:test1 @3

Possible duplicate of [Accessing the index in Python 'for' loops](http://stackoverflow.com/questions/522563/accessing-the-index-in-python-for-loops) — Łukasz Rogalski, Sep 18 '16 at 17:14

Delgan · Accepted Answer · 2016-09-18T17:22:29.283

1

You can use enumerate(), with the start argument as suggested by @JonClements:

for i, account in enumerate(y, start=1):
    print ("Trying with: %s:%s @%d" % (account[0], account[1], i))

You can also use unpacking to make the line more readable:

for i, (mail, name) in enumerate(y, start=1):
    print ("Trying with: %s:%s @%d" % (mail, name, i))

Finally, as @idjaw notified it, there is a better way to format string which is recommended over the old style:

for i, (mail, name) in enumerate(y, start=1):
    print("Trying with: {}:{} @{}".format(mail, name, i))

edited Sep 18 '16 at 17:22

answered Sep 18 '16 at 17:12

Delgan

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However, I would directly use string formatting here and just do: `"Trying with: {}:{} @{}".format(account[0], account[1], i)` – idjaw Sep 18 '16 at 17:13
You can skip the `i + 1` as `enumerate` takes a start argument: `enumerate(y, start=1)` is somewhat more explicit to what you're using `i` for. – Jon Clements Sep 18 '16 at 17:18
Also - new style string formatting wasn't introduced in Python 3 - it's been around since Python 2.6 – Jon Clements Sep 18 '16 at 17:19

score 0 · Answer 2 · answered Sep 18 '16 at 17:13

0

You're looking for enumerate:

for position, account in enumerate(y):
    print ("Trying with: %s:%s @%d" % (account[0], account[1], position))

answered Sep 18 '16 at 17:13

ForceBru

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Print the current number of item in a cycle for x in y

2 Answers2