0

Why does the Stinespring dilation of a stabilizer operation have the form

$\mathcal{E}(\rho) = tr_E(U \rho \otimes \rho_E U^\dagger)$

where $U$ is a Clifford unitary and $\rho_E$ is a stabilizer state?

Also, why does tracing out only take stabilizer states to other stabilizer states?

I am looking for an answer that applies to stabilizer subtheories for systems of any dimension.

glS
  • 24,708
  • 5
  • 34
  • 108
Si Chen
  • 129
  • 2
  • Why do you think that this formula is true? Is there a reference?. We have derived a normal of stabilizer operations (Thm. 4 in https://arxiv.org/abs/2011.11651) and it is certainly not of this form. As soon as you have somewhat non-trivial adaptive measurements, you can't find a Clifford dilation. – Markus Heinrich Dec 20 '23 at 09:47

0 Answers0