In Nielsen and Chuang, how can $\frac{1}{2(e-1)}$ result from $\frac12\int_{e-1}^{2^{t-1}-1}dl\frac{1}{l^2}$?

Question

From Nielsen and Chuang's book: $\textit{Quantum computation and quantum information}$, how can (5.34) equal (5.33)? I.e.

$$\dfrac{1}{2} \int_{e-1}^{2^{t-1}-1} dl \dfrac{1}{l^2} = \dfrac{1}{2(e-1)}.$$

As @M.Stern commented, this is probably a typo as
$$ \dfrac{1}{2} \int_{e-1}^\infty \dfrac{1}{l^2} dl = \dfrac{1}{2(e-1)} $$ — KAJ226, Nov 29 '20 at 18:57
Nielsen and Chuang errata: https://michaelnielsen.org/qcqi/errata/errata/errata.html You can check here. — Martin Vesely, Nov 30 '20 at 07:55
@MartinVesely It's not in there, is it? (It's page 224 in my old copy) — M. Stern, Nov 30 '20 at 12:26
@M.Stern: I see. Just to inform you, it is also wrong in my 10th aniversary edition (2016). — Martin Vesely, Nov 30 '20 at 18:45

score 2 · Accepted Answer · edited Jan 25 '21 at 20:49

2

It is a typo as mentioned in the comments by M Stern

edited Jan 25 '21 at 20:49

answered Jan 25 '21 at 10:45

Tejas Shetty

1 Answers1