$2^{29}$ has $9$ distinct digits. Find the missing digit without the use of a calculator.
I've seen its solution before but I still don't understand it. Math novice here. A detailed answer will be appreciated. Thanks
$2^{29}$ has $9$ distinct digits. Find the missing digit without the use of a calculator.
I've seen its solution before but I still don't understand it. Math novice here. A detailed answer will be appreciated. Thanks
You have $9$ distinct digits, one is missing from among $0$ to $9$. The sum of all should give you $45$ (why?). So if you had the sum of all digits, you could easily determine the missing one.
The next best thing is taking the number $\pmod 9$ - which gives you the sum of digits $\pmod 9$ as $10^k = 1 \pmod 9$. To show this, let $2^{29} = \sum_{k=0}^9 a_k 10^k$. Then $$2^{29} \equiv \sum_{k=0}^9a_k 10^k \equiv \sum_{k=0}^9a_k\pmod 9 $$
So in this case, this remainder gives you the answer, as you're looking for a one digit solution.
P.S. - This is a duplicate, so perhaps after studying it you could remove the Q.