I would like to calculate all the solutions to this equation using Euclides' algorithm and linear combination after finding the GCD. I suppose it's easy, but I'm a beginner.
$23x + 39y = 2$
I would like to calculate all the solutions to this equation using Euclides' algorithm and linear combination after finding the GCD. I suppose it's easy, but I'm a beginner.
$23x + 39y = 2$
Using the euclidean algorithm:
$$23x + 39y = 2$$
We have to find the $\gcd(23,39)$
Therefore,
$$39 = 23*(1) + 16$$ $$23 = 16*(1) + 7$$ $$16 = 7*(2) + 2$$ $$7 = 2*(3) + 1$$ $$2 = 1*(2)$$
so the gcd is $1$.
Now we rewrite:
$$1 = 7 - 3*(2)$$ $$1 = 7-3*(16-7*(2))$$ $$1 = 7*(7) - 3*(16)$$ $$1 = 7*(23-16) - 3*(16)$$ $$1 = 7*(23) - 10*(16)$$ $$1 = 7*(23) - 10*(39-23)$$ $$1 = 17*(23) - 10*(39)$$ So we multiply by $2$, since we get our orignial equation now:
$$2 = 34*(23) - 20*(39)$$
So one solution can be $x = 34$, and $y = -20$
Now generalizing, we find that:
$$x = 34 + \frac{39}{1}n = 34 + 39n$$ $$y = -20 - \frac{23}{1}n = -20 - 23n$$
For all integers $n$.
Look at this for more help:
comment if you have questions