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Alright I have this problem, Prove by induction $2^1+2^2+2^3+2^4+ \cdots +2^n=2(2^n-1)$

Now I've done this so far:

Base case $n=1$:

$$2^1 = 2$$

$$2(2^1-1)=2(2-1)=2(1)=2 .$$

Assume for $k$, prove for $k+1$:

$$ \begin{align*} 2^1+2^2+2^3+2^4+ \cdots +2^k+2^{k+1}

& =2(2^k-1)+2^{k+1}

\ &=2^{k+1}+2^{k+1}-2 \end{align*} $$

Now the trouble I'm running into is that I don't know how to continue from here, I know that I need to show that somehow $2^{k+1}+2^{k+1}-2 = 2(2^{k+1}-1)$.

Is there something that I would be missing with the rules of exponents, or maybe I just made a mistake and I'm doing something wrong that I don't recognize?

Any help would be appreciated, thanks.

Srivatsan
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2 Answers2

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$2^{k+1}+2^{k+1}-2 = 2\cdot 2^{k+1}-2 = 2(2^{k+1}-1)$

In first equality I use $a + a = 2a$, in second equality I factor out 2 (distributivity).

sdcvvc
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In my duplicate that I've posted in the comments, there are many ways to do this that are "not" done by induction. One good exercise for you would be to prove the exact same thing but replace $2$ with $b$ and show that $$ b^1 + b^2 + \dots + b^n = b \frac{b^n -1}{b-1} $$ for any real number $b \neq 1$. This expression comes up very often in mathematics so if you plan on doing maths a little in your life it is important that you recognize those.

Hope that helps,