If you study a little about straight lines and co-ordinate geometry, you will see that points on the same side of a straight line always have same sign of the function for that line. What I mean to say is, for a line $ax+by+c=0$, suppose a point ($x_1,y_1$) lies on the right of this line. Now if you put ($x_1,y_1$) in the expression, suppose $ax_1+by_1+c$ comes out to be positive. Now if another point ($x_2,y_2$) gives a positive value of $ax_2+by_2+c$, then it will also lie on the right side of the line.
Now, if you graph those lines, you can see that the origin lies inside the triangle:

So using the above theory, the point ($k,k^2$) should have the same sign as the constants in the equations of the lines. Then we have:
$$11k+6k^2+14>0$$
$$9k+k^2-12<0$$
$$2k+5k^2-17<0$$
If you solve those inequalities, you will get a range for k and then it is an easy task to get the integer values. I think the you will get only 2 values of k.