A function $f: \mathbb{R} \to \mathbb{R}$ is periodic if there exists a $T \neq 0$ for which $f(x+T) = f(x)$ for all $x\in \mathbb{R}$. Such a $T$ is called a period. If there is a minimum period, $T_0$, then this is called the fundamental period. (Here we mean minimum in absolute value, $|T_0| < |T|$ for all periods $T$ of $f$.)
Note that any number of the form $nT_0$ for $n\in \mathbb{Z}$ is a period for $f$, and that the fundamental period must always divide any other period. That is if $T$ is a period for $f$ then $T/T_0 \in \mathbb{Z}$.
If this were not the case then $T/T_0 = N + r$ for some $N \in \mathbb{Z}$ and $0 < r< 1$, and $$f(x)=f(x+T) = f(x + (T_0 N + T_0 r)) = f(x + T_0 r)$$ thus $T_0 r$ is a period that is smaller than $T_0$ in absolute value which is a contradiction.
Thus if $T$ is a period for $f$ and $T_0$ a fundamental period for $f$, then we have $T=nT_0$ for some $n\in\mathbb{Z}$. This is why $T_0$ is called the fundamental period.
I would add that there are periodic functions without a fundamental period. For example, a constant function is periodic with no fundamental period. Nor does the Dirichlet indicator function $$D(x) = \left\{ \begin{array}{cc} 1& x \in \mathbb{Q}\\ 0 & x \not \in \mathbb{Q}\end{array}\right.$$ have a fundamental period. I believe a sufficient condition for a periodic function to have a fundamental period is that the function be non constant and continuous for at least one point.