I am having trouble doing conformal map problems. Any suggestions on how to do this problem? Thanks.
Find a conformal bijection from $\{z : |z| > 1, Im$ $z < 5\}$ onto an annulus centered at the origin.
I am having trouble doing conformal map problems. Any suggestions on how to do this problem? Thanks.
Find a conformal bijection from $\{z : |z| > 1, Im$ $z < 5\}$ onto an annulus centered at the origin.
The boundary already consists of two circles (counting a line as a circle). We just have to make them concentric with a suitable Möbius transformation. The inner circle $|z|=1$ looks good already; let's keep it that way. Also, since both circles are symmetric about the imaginary axis, our transformation can be symmetric too: it will map the imaginary axis to itself. So, it will be
$$f(z) = \frac{z-ib}{1+ibz}$$
where $b\in(-1,1)$ is a real number to be determined. The image of $\operatorname{Im}z=5$ is symmetric about the imaginary axis; to find it, we just need to know where it crosses the axis. This is where:
$$f(5i)=\frac{5i-ib}{1-5b} = \frac{5-b}{1-5b} i, \quad f(\infty) = \frac{1}{ib} = -\frac{1}{b}i$$
These two points are endpoints of a diameter of the image. And we want the center of the image to be zero, so
$$\frac{5-b}{1-5b} = \frac{1}{b}$$
from where $b=5-2\sqrt{6}$.