If $a\ge750$ is an integer , then is it true that $\bigl(2\times17^{4a+3}\bigr)+1$ cannot be a prime ?
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Is this ever an integer? – martini Jun 03 '14 at 07:19
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2Is that period a multiplication sign? I guess so (seen it enough many times), but that always leaves me wondering? Sorry about the tag see-saw. The only thing I can tell easily is that if $a\equiv1\pmod 3$, then the number is divisible by seven. – Jyrki Lahtonen Jun 03 '14 at 07:30
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A related question. – Lucian Jun 03 '14 at 15:02
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$2*17^{4*1497+3}+1$ is prime.
So the answer is very short: No.
Edit: There are some good tools to search for primes. I used these:
For Sieving you can use NewPGen: http://primes.utm.edu/programs/NewPGen/
And for the actual proving of primality there is LLR: http://jpenne.free.fr/

Michael Stocker
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