It can be shown that if $f$ is a map of sets, $f:X\rightarrow Y$ say, that for $A_\lambda \subseteq X, \lambda \in \Lambda$, an indexing set, then:
$$f\left(\bigcup\limits_{\lambda}A_\lambda\right)=\bigcup\limits_{\lambda}f\left(A_\lambda\right)$$
and
$$f\left(\bigcap\limits_{\lambda}A_\lambda\right)\subseteq\bigcap\limits_{\lambda}f\left(A_\lambda\right).$$
I was just wondering are there functions such that equality holds for the second statement for all collections of subsets $\{A_\lambda\}_{\lambda \in \Lambda}$ of $X$ where $\bigcap\limits_{\lambda}A_\lambda \neq \emptyset$?
I would suppose constant maps to be an example. Any others? I'm just wondering if there might be a condition for it.
This seemed relevant but it relies on the sets having topologies on them, with "nice" properties.
Continuous image of the intersection of decreasing sets in a compact space
I was thinking about this in relation to a mapping of closed sets in a basis for a topology, and I suppose using topology would also be relevant then.
is:q wiki:1
might be a good place for start. – Asaf Karagila May 01 '14 at 20:33