Prove that
$$\frac{z}{(1-z)^2} = \sum_{n=1}^{\infty} nz^n.$$
Do I need to do this by induction or by any other way?
Please help.
Prove that
$$\frac{z}{(1-z)^2} = \sum_{n=1}^{\infty} nz^n.$$
Do I need to do this by induction or by any other way?
Please help.
You do not want to try this with induction. You can't form an inductive hypothesis that means anything. You are only trying to prove one statement, not a whole family of statements. What you should try to do then is a direct proof.
Here's a hint: What is the series for $\dfrac{1}{1-z}$? How can you get your left hand side from this? (There are two easy ways to do this but one way is really, really ugly.)
Whenever you have a somewhat complicated series that "looks like" a basic series that you know, you should always see if you can manipulate the basic series to get the series you have. In this case, we can see that $\dfrac{1}{1-z}$ is somehow related to our left hand side so we should try to do something with this.