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Given a Banach space B,V is a subspace of B,if B/V is finite dimension,then is it enough to show that B is closed?

Thanks!

user48537
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  • Thanks for your comment and great reference. I need to think for a while. – user48537 Apr 08 '14 at 04:23
  • Thanks for your comment and great reference. I am sorry that the following question may be unclear. Is there concrete construction that the kernel can be described concretely? – user48537 Apr 08 '14 at 04:50
  • Find any non-zero linear functional on an infinite dimensional Banach space which is not continuous. Doing that explicitly needs recourse to the axiom of choice. See http://math.stackexchange.com/questions/99206/discontinuous-linear-functional and http://mathoverflow.net/questions/31163/unbounded-linear-operator-defined-on-l2/ – Mariano Suárez-Álvarez Apr 08 '14 at 04:53

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