2

So i know that an open function is a function with the property that it sends an open interval to an open interval , but how to find a function which is open and not continous ?

Any hints ?

thanks

David Mitra
  • 74,748
kabary
  • 281

1 Answers1

1

How about the function $f(z) = \arg z$ mapping from $S_1\subseteq \mathbb C$ to $[0,2\pi)$? An image of every open set is open, but $f$ is not continuous around $1$.

5xum
  • 123,496
  • 6
  • 128
  • 204