I found this on wolfram alpha :
How does wolfram evaluate this series? How to proof that $$\sum_{n=1}^\infty \left(\frac{1}{n}+\frac{1}{2n}+...+\frac{1}{n^2}\right)^2= \frac{17\pi^4}{360} $$ ?
Thanks in advance.
I found this on wolfram alpha :
How does wolfram evaluate this series? How to proof that $$\sum_{n=1}^\infty \left(\frac{1}{n}+\frac{1}{2n}+...+\frac{1}{n^2}\right)^2= \frac{17\pi^4}{360} $$ ?
Thanks in advance.