I am in advance sorry if this question is too easy for this site, but I am having real problem understanding how to solve this summation:
$$\sum_{i=1}^n{i*2^i}$$
I understand basics of summations but i don't know where to start, please help.
I am in advance sorry if this question is too easy for this site, but I am having real problem understanding how to solve this summation:
$$\sum_{i=1}^n{i*2^i}$$
I understand basics of summations but i don't know where to start, please help.
Suppose you write $$\sum_{i=1}^n{i*2^i}$$ as $$x\sum_{i=1}^n{i*x^{i-1}}$$The term which is in the summation is the derivative of $$\sum_{i=1}^n{x^{i}}=\frac{x \left(x^n-1\right)}{x-1}$$ which is a geometric progression. So, compute the derivative of the rhs with respect to $x$, multiply the result by $x$ and replace $x$ by $2$.
I am sure you can take from here.