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Where does the series $$ \sum_{k=1}^{\infty} { \frac{\sin(kx)}{k} } \space \space \space \text{for} \space x \in \mathbb{R}$$converge/ uniformly converge and how would I show this? I have tried many of the standard tests for convergence and got nowhere.

Clement C.
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jacca
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1 Answers1

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Use Dirichlet's criterion. Can you determine when $\displaystyle \sum_{k=1}^n \sin kx$ is (uniformly) bounded? Alternatively, a nice proof starts by observing $$\frac{\sin kx}k=\int_0^x \cos kt dt$$

Pedro
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