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The coefficients may be complex.

I was doing a problem for $d=4$ and am wondering if this can this problem be generalized for any $d$

MT_
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2 Answers2

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$x$ root of $f(x)$ $\Rightarrow$ $x^n$ root of $f$ $\forall n$, but $f$ has only a finite number of roots $\Rightarrow$ $x=0$ or a $k-$th root of unit $\Rightarrow$ $f(x)$ is...

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In fact one needs only the case $\,n=2\,$ to conclude that all zeros of $f$ are roots of unity. $ $ Generally, if $\,f(x)\in\Bbb C[x],\ f(0)\ne 0\,$ is such that $f(\alpha)=0\,\Rightarrow\, f(\alpha^2)=0$ or $f(-\alpha^2) = 0,\,$ then all zeros of $f$ are roots of unity. This leads to efficient algorithms to test if a polynomial is cyclotomic (i.e. divides $\,x^k-1\,$ for some $k),\,$ or a product of cyclotomic polynomials. Follow the above link for references and further discussion.

Bill Dubuque
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