The second form throws me, that the dy appears before the second integral. I have unfortunately little skill for Calculus, and I can't seem to find a similar question online to take example from. All help would be greatly appreciated.
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1The righthand expression means the same as $$\int_0^1\int_{\sqrt{y}}^1\frac1{2+x^3}dxdy;,$$ a form that may be more familiar to you. – Brian M. Scott Dec 10 '13 at 03:38
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Invaluable! Thank you. – Plastonick Dec 10 '13 at 03:40
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You’re welcome! – Brian M. Scott Dec 10 '13 at 03:40
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Related: http://math.stackexchange.com/questions/387572/notation-why-write-the-differential-first – apnorton Dec 10 '13 at 04:03
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@anorton: Done. – Brian M. Scott Dec 10 '13 at 04:08
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The righthand expression means the same as $$\int_0^1\int_{\sqrt{y}}^1\frac1{2+x^3}dxdy\;,$$ a form that may be more familiar to you.
Brian M. Scott
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A double integral is a like a summation over two variables. In your example, the first sum is taken over a variable x, with y fixed. Let's call the resulting sum a function of y -- g(y). The 2nd sum is over a variable y, with the summands or terms equal to different values of g(y).
Kode Charlie
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