Here, I ask how to geometrically prove the limit \begin{equation}\lim_{x \to 0}\frac{1-\cos{x}}{x}\end{equation} using squeeze theorem. I see so many proofs for the other important limit \begin{equation}\lim_{x \to 0} \frac{\sin{x}}{x}\end{equation} But it seems that no one discussed the first one yet.
Asked
Active
Viewed 96 times
1
-
2Just curious, but do you HAVE to use squeeze theorem? THere are so many other ways to do this limit – imranfat Dec 02 '13 at 18:52
-
Yes, I HAVE to use squeeze theorem. – Burak ER Dec 03 '13 at 07:15