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$e^{\pi}$ or $\pi^e$, Can we find which one is bigger by using calculus?

Thanks.

mesel
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1 Answers1

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$$e^\pi>\pi^e\iff\pi>e\log\pi\iff\frac{\log e}e=\frac1e>\frac{\log\pi}\pi$$

Now look at the function

$$f(x):=\frac{\log x}x\;,\;\;x\ge e\implies f'(x)=\frac{1-\log x}{x^2}\le0\implies f(x)$$

is monotone descending, and thus

$$e<\pi\implies \frac1e=\frac{\log e}e=f(e)>f(\pi)=\frac{\log\pi}\pi$$

DonAntonio
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