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Consider $\Bbb Q$ with subspace topology and $\Bbb Q\times \Bbb Q$ with product topology. Why this two spaces are not homeomorphic?($\Bbb Q$ is the rational numbers)

leo
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Aliakbar
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1 Answers1

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It is a theorem of Sierpinski that every countable metric space without isolated points is homeomorphic to $\mathbb{Q}$. See eg here. $\mathbb{Q}^2$ is a countable metric space without isolated points. Therefore these two spaces are homeomorphic.

Najib Idrissi
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