Consider $\Bbb Q$ with subspace topology and $\Bbb Q\times \Bbb Q$ with product topology. Why this two spaces are not homeomorphic?($\Bbb Q$ is the rational numbers)
Asked
Active
Viewed 370 times
7
1 Answers
10
It is a theorem of Sierpinski that every countable metric space without isolated points is homeomorphic to $\mathbb{Q}$. See eg here. $\mathbb{Q}^2$ is a countable metric space without isolated points. Therefore these two spaces are homeomorphic.

Najib Idrissi
- 54,185
Are the rationals homeomorphic to any power of the rationals?
– leo Nov 09 '13 at 18:46