Convert Hexadecimal number to Octal - $(FD56.52A)_{16}$ to octal
My answer - $(176526.2452)_8$
Convert Octal to Hexadecimal $(37.27)_8$
My answer - $(1F.5C)_{16}$.
Correct or incorrect?
Please help.
Convert Hexadecimal number to Octal - $(FD56.52A)_{16}$ to octal
My answer - $(176526.2452)_8$
Convert Octal to Hexadecimal $(37.27)_8$
My answer - $(1F.5C)_{16}$.
Correct or incorrect?
Please help.
The easiest way to do that is perhaps to go trought binary
$ FD56.52A_{16}= 1111\ 1101\ 0101\ 0110.0101\ 0010\ 1010_2 $
and then to form groups of 3 digits left and right from the decimal point and padding with zeros the extremes if necessary
$ FD56.52A16_{16}= 001\ 111\ 110\ 101\ 010\ 110.010\ 100\ 101\ 010_2 =176526.2452_8$
So I think your answer is correct.
The other is the same but reversed .
First of all, use $ {inline formula} $
and $$ {paragraph formula} $$
to typeset mathematics, to get proper subscripts.
One strategy is to just convert to decimal and back, but a much better strategy is to remember that in hexadecimal each digit corresponds to four binary digits ($2^4=16$) and in octal each digit is three bits ($2^3=8$).
$$ ({\rm FD56.52A})_{16} = (1111'1101'0101'0110\,.0101'0010'1010)_2 $$
Then we regroup to three digits and pad with zeros:
$$ (001'111'110'101'010'110\,.010'100'101'010)_2 = (176526.2452)_8 $$
You can use this method the other around way too.